What is the domain of f(x)=\sqrt[4]{(x-2)(x-3)} ?

The domain of f(x)=\sqrt[4]{(x-2)(x-3)} is x = 3

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domain of f(x)=\sqrt[4]{(x-2)(x-3)}

domain

x \leq 2 or x \geq 3

Interval Notation

(- \infty, 2] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 3

The function domain

x \leq 2 or x \geq 3

f (x) = \frac{x - 4}{x + 5}

\frac{2 x}{x - 1}

f (x) = (2 \cdot x + 3) e^{(5 \cdot x)}

\frac{2}{( x + 1 ) ^{3}}

e^{x + 6}

What is the domain of f(x)=\sqrt[4]{(x-2)(x-3)} ?
The domain of f(x)=\sqrt[4]{(x-2)(x-3)} is x<= 2\lor x>= 3