What is the domain of y=(x^2+7x-1)/(x-1) ?

The domain of y=(x^2+7x-1)/(x-1) is x 1

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domain of y=(x^2+7x-1)/(x-1)

domain

y = \frac{x ^{2} + 7 x - 1}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

12 x + 1

f (x) = lo g_{2} (2 - ∣ 3 - x ∣)

f (r) = 4 - r

f (x) = \frac{x - 1}{x + 4}

\frac{5 x - 2}{7 x + 3}

What is the domain of y=(x^2+7x-1)/(x-1) ?
The domain of y=(x^2+7x-1)/(x-1) is x<1\lor x>1