What is the shift y=5cos(2x+pi/2) ?

The shift y=5cos(2x+pi/2) is Phase:-pi/4 , Vertical:0

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shift y=5cos(2x+pi/2)

shift

y = 5 cos (2 x + \frac{π}{2})

Phase : - \frac{π}{4}, Vertical : 0

Solution steps

f (x) = 5 cos (2 x + \frac{π}{2})

g (B x - C) = cos (2 x + \frac{π}{2}), B = 2, C = - \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{2}}{2}

- \frac{π}{4}

The vertical shift

D

0

0

(0, - 2), (2, 6)

y = x + 1

x^{2} - 5 x + 3

m = \frac{0 - 5 - 0}{0 - 5 - 0}

f (x) = \frac{x}{x - 2}

What is the shift y=5cos(2x+pi/2) ?
The shift y=5cos(2x+pi/2) is Phase:-pi/4 , Vertical:0