What is the asymptotes of f(x)=(x^2-9)/(x+1) ?

The asymptotes of f(x)=(x^2-9)/(x+1) is Vertical: x=-1,Slant: y=x-1

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asymptotes of f(x)=(x^2-9)/(x+1)

asymptotes

f (x) = \frac{x ^{2} - 9}{x + 1}

Vertical : x = - 1, Slant : y = x - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 9}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} - 9}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} - 9}{x + 1} : y = x - 1

Vertical : x = - 1, Slant : y = x - 1

f (x) = x - 5

f (x) = t^{4} - 8 t^{3} + 10 t^{2}

x - 5 y - 3 = 0, (8, - 7)

y = 3 x + 1

f (x) = \frac{x}{x ^{2} + 20}

What is the asymptotes of f(x)=(x^2-9)/(x+1) ?
The asymptotes of f(x)=(x^2-9)/(x+1) is Vertical: x=-1,Slant: y=x-1