What is the perpendicular y= 1/3 x ?

The perpendicular y= 1/3 x is y=-3x+b

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perpendicular y= 1/3 x

perpendicular

y = \frac{1}{3} x

y = - 3 x + b

Solution steps

Find the slope of

y = \frac{1}{3} x : m = \frac{1}{3}

Compute the slope of the perpendicular line:

m_{p} = - 3

Line with slope m=

- 3 : y = - 3 x + b

y = - 3 x + b

f (x) = x^{3} + 4 x^{2} - 4 x - 16

\frac{2}{5} x - 6

f (x) = 2 csc (\frac{x}{3})

\frac{4}{x ^{2} + 8}