What is the domain of f(x)=x^2sqrt(x^2-9) ?

The domain of f(x)=x^2sqrt(x^2-9) is x = 3

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domain of f(x)=x^2sqrt(x^2-9)

domain

f (x) = x^{2} x^{2} - 9

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

f (x) = \frac{5 x}{3} + 5

f (x) = \frac{x ^{2} + 8 x + 15}{x + 3}

\frac{x ^{2} - 8 x}{x + 2}

y = csc (x)

\frac{2}{x} - 3

What is the domain of f(x)=x^2sqrt(x^2-9) ?
The domain of f(x)=x^2sqrt(x^2-9) is x<=-3\lor x>= 3