What is the inverse of f(x)=4^{x+1}-2 ?

The inverse of f(x)=4^{x+1}-2 is (ln(x+2))/(2ln(2))-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=4^{x+1}-2

inverse

f (x) = 4^{x + 1} - 2

\frac{ln ( x + 2 )}{2 ln ( 2 )} - 1

Solution steps

y = 4^{x + 1} - 2

Replace

x

with

y

x = 4^{y + 1} - 2

Solve for

y, x = 4^{y + 1} - 2

\frac{ln ( x + 2 )}{2 ln ( 2 )} - 1

sin (3 x)

y = - 2 x + 2, (1, 4)

y = 5 x - 7

f (x) = 8 - 6 x

\frac{x + 1}{1 - ∣ x ∣}

What is the inverse of f(x)=4^{x+1}-2 ?
The inverse of f(x)=4^{x+1}-2 is (ln(x+2))/(2ln(2))-1