What is the inverse of f(x)=8-3/(x^2) ?

The inverse of f(x)=8-3/(x^2) is sqrt(-3/(x-8)),-sqrt(-3/(x-8))

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inverse of f(x)=8-3/(x^2)

inverse

f (x) = 8 - \frac{3}{x ^{2}}

- \frac{3}{x - 8}, - - \frac{3}{x - 8}

Solution steps

y = 8 - \frac{3}{x ^{2}}

Replace

x

with

y

x = 8 - \frac{3}{y ^{2}}

Solve for

y, x = 8 - \frac{3}{y ^{2}}

- \frac{3}{x - 8}, - - \frac{3}{x - 8}

cos (x) - 3

y = - x + 7

f (x) = - x + 3

f (x) = x - 4

What is the inverse of f(x)=8-3/(x^2) ?
The inverse of f(x)=8-3/(x^2) is sqrt(-3/(x-8)),-sqrt(-3/(x-8))