What is the perpendicular y=5x2,(1,1) ?

The perpendicular y=5x2,(1,1) is y=-1/10 x+11/10

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perpendicular y=5x2,(1,1)

perpendicular

y = 5 x 2, (1, 1)

y = - \frac{1}{10} x + \frac{11}{10}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 5 x 2

that passes through

(1, 1)

Find the slope of

y = 5 x 2 : m = 10

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{10}

Find the line with slope m=

- \frac{1}{10}

and passing through

(1, 1) : y = - \frac{1}{10} x + \frac{11}{10}

y = - \frac{1}{10} x + \frac{11}{10}

f (x) = - 6 x + 2

y = - 3 tan (\frac{1}{2} x)

f (x) = 7 - 4 x

lo g_{4} (x - 10)

f (x) = \frac{x ^{2} + 1}{x ^{2} + 2}

What is the perpendicular y=5x2,(1,1) ?
The perpendicular y=5x2,(1,1) is y=-1/10 x+11/10