What is the domain of f(x)=(sqrt(x-3))^2 ?

The domain of f(x)=(sqrt(x-3))^2 is x>= 3

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domain of f(x)=(sqrt(x-3))^2

domain

f (x) = (x - 3)^{2}

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

\frac{2 x + 1}{x}

\frac{x}{( x + 2 ) ( x + 4 )}

x^{2} - 2 x + 2

x + 6 + 2

f (x) = \frac{x ^{2} + 5 x + 6}{x ^{2} - 9}

What is the domain of f(x)=(sqrt(x-3))^2 ?
The domain of f(x)=(sqrt(x-3))^2 is x>= 3