What is the range of f(x)=arccos(x/5) ?

The range of f(x)=arccos(x/5) is 0<= f(x)<= pi

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range of f(x)=arccos(x/5)

range

f (x) = arccos (\frac{x}{5})

0 \leq f (x) \leq π

Interval Notation

[0, π]

Solution steps

The range of the basic

arccos

function is

0 \leq arccos (\frac{x}{5}) \leq π

0 \leq arccos (\frac{x}{5}) \leq π

Therefore the range is

0 \leq f (x) \leq π

y = x

f (x) = \frac{4 x + 9}{3 x - 4}

f (x) = \frac{cos ( \frac{1}{x} )}{1 + \frac{1}{x}}

\frac{4 x - 8}{( x - 4 ) ( x + 1 )}

\frac{x ^{2} - 36}{x - 6}

What is the range of f(x)=arccos(x/5) ?
The range of f(x)=arccos(x/5) is 0<= f(x)<= pi