What is the domain of f(s)=(sqrt(s-3))/(s-6) ?

The domain of f(s)=(sqrt(s-3))/(s-6) is 3 6

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domain of f(s)=(sqrt(s-3))/(s-6)

domain

f (s) = \frac{s - 3}{s - 6}

3 \leq s < 6 or s > 6

Interval Notation

[3, 6) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

s \geq 3

Find undefined (singularity) points:

s = 6

Combine real regions and undefined points for final function domain

3 \leq s < 6 or s > 6

(9, - 3), (5, - 1)

\frac{6}{x}

\frac{6}{x} + 8

6 x^{4} + 32 x^{3}

f (x) = (x + 10)^{2} (x - 5)

What is the domain of f(s)=(sqrt(s-3))/(s-6) ?
The domain of f(s)=(sqrt(s-3))/(s-6) is 3<= s<6\lor s>6