What is the domain of f(x)=log_{3}(x^2-1) ?

The domain of f(x)=log_{3}(x^2-1) is x 1

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domain of f(x)=log_{3}(x^2-1)

domain

f (x) = lo g_{3} (x^{2} - 1)

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

The function domain

x < - 1 or x > 1

f (x) = 3^{x + 1} - 6

g (x) = 3 + x

- 3 x^{4} + 28 x^{3} - 60 x^{2}

y = 2 x - 3

f (x) = \frac{1 - x ^{2}}{x ^{2} + 1}

What is the domain of f(x)=log_{3}(x^2-1) ?
The domain of f(x)=log_{3}(x^2-1) is x<-1\lor x>1