What is the inverse of f(x)=4(x+2)^2+5 ?

The inverse of f(x)=4(x+2)^2+5 is (sqrt(x-5))/2-2,-(sqrt(x-5))/2-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=4(x+2)^2+5

inverse

f (x) = 4 (x + 2)^{2} + 5

\frac{x - 5}{2} - 2, - \frac{x - 5}{2} - 2

Solution steps

y = 4 (x + 2)^{2} + 5

Replace

x

with

y

x = 4 (y + 2)^{2} + 5

Solve for

y, x = 4 (y + 2)^{2} + 5

\frac{x - 5}{2} - 2, - \frac{x - 5}{2} - 2

f (x) = - \frac{1}{4} x - 7

y = - 7 sec (π x)

f (x) = x^{2} + 8 x + 7

3 x^{2} - 16 x + 5

f (x) = \frac{3}{x} + 5

What is the inverse of f(x)=4(x+2)^2+5 ?
The inverse of f(x)=4(x+2)^2+5 is (sqrt(x-5))/2-2,-(sqrt(x-5))/2-2