What is the asymptotes of f(x)=(x^2-4)/(x^2-9) ?

The asymptotes of f(x)=(x^2-4)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1

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asymptotes of f(x)=(x^2-4)/(x^2-9)

asymptotes

f (x) = \frac{x ^{2} - 4}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 1

(\frac{5}{4})^{x}

- 3 x^{2} - 12 x - 3

x^{\frac{1}{3}}

f (x) = 5 x^{2} - 7

f (x) = \frac{1}{( 2 - x ) + 1}

What is the asymptotes of f(x)=(x^2-4)/(x^2-9) ?
The asymptotes of f(x)=(x^2-4)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1