What is the domain of f(x)=sqrt(x-2)^2-2 ?

The domain of f(x)=sqrt(x-2)^2-2 is x>= 2

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domain of f(x)=sqrt(x-2)^2-2

domain

f (x) = x - 2^{2} - 2

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

4 - x + x^{2} - 1

f (x) = (3 x + 2)^{3}

\frac{- 5 + 12 x + 49}{6}

\frac{4 x - 3}{x + 8}

x - 3 y = 2

What is the domain of f(x)=sqrt(x-2)^2-2 ?
The domain of f(x)=sqrt(x-2)^2-2 is x>= 2