What is the range of 2sqrt(x+3)+1 ?

The range of 2sqrt(x+3)+1 is f(x)>= 1

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range of 2sqrt(x+3)+1

range

2 x + 3 + 1

f (x) \geq 1

Interval Notation

[1, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 1

f (x) \geq 1

y = - \frac{1}{2} x - 2

5 sin (x)

f (x) = 2 sin (3 x - 18) + 3

(0, \frac{1}{6}), (- \frac{6}{7}, 0)

(1, 3), (13, 8)