What is the domain of f(x)=[sqrt([5x-15])]+40 ?

The domain of f(x)=[sqrt([5x-15])]+40 is x>= 3

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domain of f(x)=[sqrt([5x-15])]+40

domain

f (x) = [[5 x - 15]] + 40

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

f (x) = \frac{3}{10} x + \frac{3}{2}

f (x) = \frac{4 x}{x ^{3} - 4 x}

f (x) = \frac{- 2 x ^{3}}{( x - 3 )}

x - 3 y = - 3

\frac{x}{x ^{2} - 6 x + 8}

What is the domain of f(x)=[sqrt([5x-15])]+40 ?
The domain of f(x)=[sqrt([5x-15])]+40 is x>= 3