What is the inverse of f(x)=2x^2-8 ?

The inverse of f(x)=2x^2-8 is sqrt((x+8)/2),-sqrt((x+8)/2)

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inverse of f(x)=2x^2-8

inverse

f (x) = 2 x^{2} - 8

\frac{x + 8}{2}, - \frac{x + 8}{2}

Solution steps

y = 2 x^{2} - 8

Replace

x

with

y

x = 2 y^{2} - 8

Solve for

y, x = 2 y^{2} - 8

\frac{x + 8}{2}, - \frac{x + 8}{2}

y = - 4 x - 1, (2, - 4)

f (x) = \frac{x + 8}{x + 6}

f (x) = \frac{6 x}{10 x - 7}

(3 - 6 t)^{\frac{5}{2}}

\frac{x ^{2} + 1}{2}

What is the inverse of f(x)=2x^2-8 ?
The inverse of f(x)=2x^2-8 is sqrt((x+8)/2),-sqrt((x+8)/2)