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Popular >

distance (5,-5),(7,-2)

Solution

distance

(5, - 5), (7, - 2)

Solution

13

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, - 5)

and

(7, - 2)

is

= (7 - 5)^{2} + (- 2 - (- 5))^{2}

Simplify

= 13

Popular Examples

inverse of f(x)=3x+5 inverse

f (x) = 3 x + 5

critical sqrt(x)critical points

x

amplitude of f(t)=-5sin(7t-1)amplitude

f (t) = - 5 sin (7 t - 1)

asymptotes of f(x)=(2x)/(4-x)asymptotes

f (x) = \frac{2 x}{4 - x}

asymptotes of (x-2)/(x^2-4)asymptotes

\frac{x - 2}{x ^{2} - 4}

Frequently Asked Questions (FAQ)

What is the distance (5,-5),(7,-2) ?
The distance (5,-5),(7,-2) is square root of 13