en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

distance (7,9),(11,5)

Solution

distance

(7, 9), (11, 5)

Solution

42

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(7, 9)

and

(11, 5)

is

= (11 - 7)^{2} + (5 - 9)^{2}

Simplify

= 42

Popular Examples

f (x) = x^{2} - 3 x + 2

inverse of (5x+6)/9 inverse

\frac{5 x + 6}{9}

symmetry x^2+(y+3)^2=16 symmetry

x^{2} + (y + 3)^{2} = 16

parity f(x)=x^5-3x^3 parity

f (x) = x^{5} - 3 x^{3}

range of f(x)=-x^2+2x+3 range

f (x) = - x^{2} + 2 x + 3

Frequently Asked Questions (FAQ)

What is the distance (7,9),(11,5) ?
The distance (7,9),(11,5) is 4sqrt(2)