What is the perpendicular 1/2 x-y=-2,(2,4) ?

The perpendicular 1/2 x-y=-2,(2,4) is y=-2x+8

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perpendicular 1/2 x-y=-2,(2,4)

perpendicular

\frac{1}{2} x - y = - 2, (2, 4)

y = - 2 x + 8

Solution steps

Find the line

y = mx + b

perpendicular to

\frac{1}{2} x - y = - 2

that passes through

(2, 4)

Find the slope of

\frac{1}{2} x - y = - 2 : m = \frac{1}{2}

Compute the slope of the perpendicular line:

m_{p} = - 2

Find the line with slope m=

- 2

and passing through

(2, 4) : y = - 2 x + 8

y = - 2 x + 8

f (x) = \frac{1}{- 10 x + 3}

f (x) = lo g_{5} (∣ x ∣)

\frac{3}{x - 1}

\frac{x ^{2} + 4}{x ^{2} - 4}

f (x) = \frac{ln ( x )}{x ^{2}}

What is the perpendicular 1/2 x-y=-2,(2,4) ?
The perpendicular 1/2 x-y=-2,(2,4) is y=-2x+8