What is the asymptotes of f(x)=((x^2+1))/(7x-2x^2) ?

The asymptotes of f(x)=((x^2+1))/(7x-2x^2) is Vertical: x=0,x= 7/2 ,Horizontal: y=-1/2

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asymptotes of f(x)=((x^2+1))/(7x-2x^2)

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{7 x - 2 x ^{2}}

Vertical : x = 0, x = \frac{7}{2}, Horizontal : y = - \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{7 x - 2 x ^{2}} : x = 0, x = \frac{7}{2}

Horizontal Asymptotes of

\frac{x ^{2} + 1}{7 x - 2 x ^{2}} : y = - \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} + 1}{7 x - 2 x ^{2}} :

None

Vertical : x = 0, x = \frac{7}{2}, Horizontal : y = - \frac{1}{2}

3 y - 6 = 3 x

(6.6) (3.3)

f (x) = x^{2} + 4

f (x) = 20 x^{3} - 5 x^{4}

\frac{x}{x ^{2} - 16}

What is the asymptotes of f(x)=((x^2+1))/(7x-2x^2) ?
The asymptotes of f(x)=((x^2+1))/(7x-2x^2) is Vertical: x=0,x= 7/2 ,Horizontal: y=-1/2