What is the inverse of f(x)=(1-e^x)/(1+e^x) ?

The inverse of f(x)=(1-e^x)/(1+e^x) is ln((1-x)/(x+1))

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inverse of f(x)=(1-e^x)/(1+e^x)

inverse

f (x) = \frac{1 - e ^{x}}{1 + e ^{x}}

ln (\frac{1 - x}{x + 1})

Solution steps

y = \frac{1 - e ^{x}}{1 + e ^{x}}

Replace

x

with

y

x = \frac{1 - e ^{y}}{1 + e ^{y}}

Solve for

y, x = \frac{1 - e ^{y}}{1 + e ^{y}}

ln (\frac{1 - x}{x + 1})

f (x) = \frac{13}{x - 7}

f (x) = 12 - x^{2}

2 x^{3} - 6 x^{2} + 4

f (z) = \frac{46}{x}

f (x) = \frac{x}{x ^{2} + 81}

What is the inverse of f(x)=(1-e^x)/(1+e^x) ?
The inverse of f(x)=(1-e^x)/(1+e^x) is ln((1-x)/(x+1))