What is the y=-7/2 x-10,\at 7x-2y-2=0 ?

The y=-7/2 x-10,\at 7x-2y-2=0 is (-7/2 x-10)\circ \at 7x-2(-7/2 x-10)-2

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y=-7/2 x-10,\at 7x-2y-2=0

y = - \frac{7}{2} x - 10, at 7 x - 2 y - 2 = 0

(- \frac{7}{2} x - 10) \circ at 7 x - 2 (- \frac{7}{2} x - 10) - 2

Solution steps

Find

y \circ at 7 x - 2 y - 2

given

y = - \frac{7}{2} x - 10, at 7 x - 2 y - 2 = 0

y = - \frac{7}{2} x - 10

y = - \frac{7}{2} x - 10

= (- \frac{7}{2} x - 10) \circ at 7 x - 2 (- \frac{7}{2} x - 10) - 2

f (x) = 8 - x^{2}

\frac{4}{\frac{4}{x}}

f (x) = - 7 cos (4 x)

f (x) = x e^{x}

(4, 2), (1, - 2)

What is the y=-7/2 x-10,\at 7x-2y-2=0 ?
The y=-7/2 x-10,\at 7x-2y-2=0 is (-7/2 x-10)\circ \at 7x-2(-7/2 x-10)-2