What is the critical f(x)=x+4/(x^2) ?

The critical f(x)=x+4/(x^2) is x=2

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critical f(x)=x+4/(x^2)

critical points

f (x) = x + \frac{4}{x ^{2}}

x = 2

Solution steps

x + \frac{4}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

x + \frac{4}{x ^{2}} : x < 0 or x > 0

x + \frac{4}{x ^{2}}

is not defined at

x = 0

, therefore:

x = 2

y = cos (sin (tan (9 x)))

36 - x^{2} - x + 1

3 y - 6 = 0

\frac{2 x}{x ^{2} + 9}

f (x) = \frac{3 x}{x ( x ^{2} - 16 )}