What is the inverse of f(x)=(x+3)/(x+10) ?

The inverse of f(x)=(x+3)/(x+10) is (3-10x)/(x-1)

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inverse of f(x)=(x+3)/(x+10)

inverse

f (x) = \frac{x + 3}{x + 10}

\frac{3 - 10 x}{x - 1}

Solution steps

y = \frac{x + 3}{x + 10}

Replace

x

with

y

x = \frac{y + 3}{y + 10}

Solve for

y, x = \frac{y + 3}{y + 10}

\frac{3 - 10 x}{x - 1}

f (x) = 3 x + 3

x^{3} - 5 x^{2} - x + 4

arcsin (3 x)

y = 4 x + 2

f (x) = 3 x^{2} + 2 x^{4} - 2

What is the inverse of f(x)=(x+3)/(x+10) ?
The inverse of f(x)=(x+3)/(x+10) is (3-10x)/(x-1)