What is the critical 2e^{2x}-e^x ?

The critical 2e^{2x}-e^x is x=-2ln(2)

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critical 2e^{2x}-e^x

critical points

2 e^{2 x} - e^{x}

x = - 2 ln (2)

Solution steps

2 e^{2 x} - e^{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2 ln (2)

Identify critical points not in

f (x)

domain

Domain of

2 e^{2 x} - e^{x} : - \infty < x < \infty

All critical points are in domain

x = - 2 ln (2)

x^{2} + 8 x - 65

y = - \frac{7}{6} x + 6, (6, 4)

(9, - 2), (- 1, 8)

f (x) = \frac{3 - x ^{3}}{4}