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Popular >

range of f(x)= 6/5 x^2+3/2

Solution

range

f (x) = \frac{6}{5} x^{2} + \frac{3}{2}

Solution

f (x) \geq \frac{3}{2}

+1

Interval Notation

[\frac{3}{2}, \infty)

Solution steps

Vertex of

\frac{6}{5} x^{2} + \frac{3}{2} :

Minimum

(0, \frac{3}{2})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = \frac{6}{5},

Vertex

(x_{v}, y_{v}) = (0, \frac{3}{2})

f (x) \geq \frac{3}{2}

Popular Examples

distance (11.2,-2.2),(5.2,-10.2)distance

(11.2, - 2.2), (5.2, - 10.2)

inverse of f(x)=-1/4 x+15 inverse

f (x) = - \frac{1}{4} x + 15

inverse of f(x)= 9/x+4 inverse

f (x) = \frac{9}{x} + 4

range of f(x)=sqrt(1-(x-2)^2)range

f (x) = 1 - (x - 2)^{2}

extreme f(x)=12x^{2/3}-x extreme points

f (x) = 12 x^{\frac{2}{3}} - x

Frequently Asked Questions (FAQ)

What is the range of f(x)= 6/5 x^2+3/2 ?
The range of f(x)= 6/5 x^2+3/2 is f(x)>= 3/2