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Popular >

inverse of sqrt(1+t^2)

Solution

inverse

1 + t^{2}

Solution

t^{2} - 1, - t^{2} - 1

Solution steps

y = 1 + t^{2}

Replace

t

with

y

t = 1 + y^{2}

Solve for

y, t = 1 + y^{2}

t^{2} - 1, - t^{2} - 1

Popular Examples

range of f(x)=3sin(pix)range

f (x) = 3 sin (π x)

parity y=2t+tan(t)parity

y = 2 t + tan (t)

domain of f(x)=(sqrt(x+1))/(5x+4)domain

f (x) = \frac{x + 1}{5 x + 4}

range of y=(x-1)/(x^2-9)range

y = \frac{x - 1}{x ^{2} - 9}

symmetry y= 5/x symmetry

y = \frac{5}{x}

Frequently Asked Questions (FAQ)

What is the inverse of sqrt(1+t^2) ?
The inverse of sqrt(1+t^2) is sqrt(t^2-1),-sqrt(t^2-1)