What is the perpendicular y=5x+2,(1,1) ?

The perpendicular y=5x+2,(1,1) is y=-1/5 x+6/5

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perpendicular y=5x+2,(1,1)

perpendicular

y = 5 x + 2, (1, 1)

y = - \frac{1}{5} x + \frac{6}{5}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 5 x + 2

that passes through

(1, 1)

Find the slope of

y = 5 x + 2 : m = 5

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{5}

Find the line with slope m=

- \frac{1}{5}

and passing through

(1, 1) : y = - \frac{1}{5} x + \frac{6}{5}

y = - \frac{1}{5} x + \frac{6}{5}

f (x) = \frac{3 x - x ^{2}}{x ^{4} - 9 x ^{2}}

f (x) = \frac{x ^{3}}{x ^{2} - 4 x - 96}

f (x) = - x^{2} - 4

(5, - 2), (- 1, 3)

f (x) = \frac{2}{t ^{2} + 4}

What is the perpendicular y=5x+2,(1,1) ?
The perpendicular y=5x+2,(1,1) is y=-1/5 x+6/5