What is the critical f(x)= x/(x^2+7x+6) ?

The critical f(x)= x/(x^2+7x+6) is x=-sqrt(6),x=sqrt(6)

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critical f(x)= x/(x^2+7x+6)

critical points

f (x) = \frac{x}{x ^{2} + 7 x + 6}

x = - 6, x = 6

Solution steps

\frac{x}{x ^{2} + 7 x + 6}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 6, x = 6, x = - 6, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 7 x + 6} : x < - 6 or - 6 < x < - 1 or x > - 1

\frac{x}{x ^{2} + 7 x + 6}

is not defined at

x = - 6, x = - 1

, therefore:

x = - 6, x = 6

f (x) = 4 x - 3

ln (64.86)

f (x) = \frac{- x ^{2}}{x + 1}

\frac{x ^{2} + x - 12}{x ^{2} - 4}

f (x) = t - 7

What is the critical f(x)= x/(x^2+7x+6) ?
The critical f(x)= x/(x^2+7x+6) is x=-sqrt(6),x=sqrt(6)