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Popular >

extreme ln(x^2+1)

Solution

extreme points

ln (x^{2} + 1)

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{2 x}{x ^{2} + 1}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

ln (x^{2} + 1) : 0

Minimum (0, 0)

Popular Examples

asymptotes of f(x)=(x+5)/(x^2-16)asymptotes

f (x) = \frac{x + 5}{x ^{2} - 16}

asymptotes of f(x)=(x^2+3x-10)/(x^2-4)asymptotes

f (x) = \frac{x ^{2} + 3 x - 10}{x ^{2} - 4}

domain of f(x)=(3x+2)/(sqrt(x^2-7x))domain

f (x) = \frac{3 x + 2}{x ^{2} - 7 x}

inverse of f(x)=-1/3 x-6 inverse

f (x) = - \frac{1}{3} x - 6

symmetry y=(x^2+1)/x symmetry

y = \frac{x ^{2} + 1}{x}

Frequently Asked Questions (FAQ)

What is the extreme ln(x^2+1) ?
The extreme ln(x^2+1) is Minimum(0,0)