What is the range of f(x)=e^{x+1}-1 ?

The range of f(x)=e^{x+1}-1 is f(x)>-1

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range of f(x)=e^{x+1}-1

range

f (x) = e^{x + 1} - 1

f (x) > - 1

Interval Notation

(- 1, \infty)

Solution steps

The range of an exponential function of the form

c \cdot n^{a x + b} + k

f (x) > k

k = - 1

f (x) > - 1

(- 3, 0), (0, - 2)

f (x) = \frac{4}{3 + x}

f (x) = 4 x^{\frac{3}{7}} - x^{\frac{4}{7}}

(- 8, 4), (- 4, - 4)

f (x) = (x - 9)^{\frac{2}{3}}