What is the range of f(x)= 1/(x+7) ?

The range of f(x)= 1/(x+7) is f(x) 0

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range of f(x)= 1/(x+7)

range

f (x) = \frac{1}{x + 7}

f (x) < 0 or f (x) > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{1}{x + 7}

Inverse of

\frac{1}{x + 7} : \frac{1}{x} - 7

\frac{1}{x} - 7

Find the domain of each inverse function

Domain of

\frac{1}{x} - 7 : x < 0 or x > 0

Combine the intervals

f (x) < 0 or f (x) > 0

f (x) = 8 ln (x) - x^{2}

y = 2 x - 4

f (x) = - \frac{3}{x - 2} - 1

793

f (x) = 3 cos (\frac{1}{2} π x - π) - 3

What is the range of f(x)= 1/(x+7) ?
The range of f(x)= 1/(x+7) is f(x)<0\lor f(x)>0