What is the inverse of f(x)=(8x)/(x^2+49) ?

The inverse of f(x)=(8x)/(x^2+49) is (4+sqrt(-49x^2+16))/x ,(4-sqrt(-49x^2+16))/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(8x)/(x^2+49)

inverse

f (x) = \frac{8 x}{x ^{2} + 49}

\frac{4 + - 49 x ^{2} + 16}{x}, \frac{4 - - 49 x ^{2} + 16}{x}

Solution steps

y = \frac{8 x}{x ^{2} + 49}

Replace

x

with

y

x = \frac{8 y}{y ^{2} + 49}

Solve for

y, x = \frac{8 y}{y ^{2} + 49}

\frac{4 + - 49 x ^{2} + 16}{x}, \frac{4 - - 49 x ^{2} + 16}{x}

f (x) = (x^{2} - 9)^{2}

f (x) = (x^{2} - 9)^{\frac{1}{3}}

f (x) = \frac{8}{x - 1}

y = ∣ x ∣

m = 0.5, (4, - 2)

What is the inverse of f(x)=(8x)/(x^2+49) ?
The inverse of f(x)=(8x)/(x^2+49) is (4+sqrt(-49x^2+16))/x ,(4-sqrt(-49x^2+16))/x