What is the asymptotes of f(x)=(x^2+1)/(x-3) ?

The asymptotes of f(x)=(x^2+1)/(x-3) is Vertical: x=3,Slant: y=x+3

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asymptotes of f(x)=(x^2+1)/(x-3)

asymptotes

f (x) = \frac{x ^{2} + 1}{x - 3}

Vertical : x = 3, Slant : y = x + 3

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x - 3} : x = 3

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x - 3} :

None

Slant Asymptotes of

\frac{x ^{2} + 1}{x - 3} : y = x + 3

Vertical : x = 3, Slant : y = x + 3

f (x) = \frac{- 2 x - 7}{3 x - 1}

f (x) = \frac{x ^{2} - 1}{x ^{3} - 2 x ^{2} + x}

f (y) = x - 4

f (x) = \frac{( 1 + e ^{- x} )}{e ^{x}}

x tan (x)

What is the asymptotes of f(x)=(x^2+1)/(x-3) ?
The asymptotes of f(x)=(x^2+1)/(x-3) is Vertical: x=3,Slant: y=x+3