What is the domain of f(x)=sqrt(x^2-4) ?

The domain of f(x)=sqrt(x^2-4) is x = 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x^2-4)

domain

f (x) = x^{2} - 4

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

f (x) = 9 x^{2} + 2 x^{3}

f (x) = \frac{4 x ^{4}}{2 x ^{2} - 3}

\frac{12 x ^{4} + 10 x - 3}{3 x ^{4}}

\frac{1}{2} (3 x - 1)

f (x) = \frac{x + 9}{x ^{2} - 81}

What is the domain of f(x)=sqrt(x^2-4) ?
The domain of f(x)=sqrt(x^2-4) is x<=-2\lor x>= 2