What is the asymptotes of f(x)=(5+2^x)/(1-2^x) ?

The asymptotes of f(x)=(5+2^x)/(1-2^x) is Vertical: x=0,Horizontal: y=-1,y=5

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asymptotes of f(x)=(5+2^x)/(1-2^x)

asymptotes

f (x) = \frac{5 + 2 ^{x}}{1 - 2 ^{x}}

Vertical : x = 0, Horizontal : y = - 1, y = 5

Solution steps

Vertical asymptotes of

\frac{5 + 2 ^{x}}{1 - 2 ^{x}} : x = 0

Horizontal Asymptotes of

\frac{5 + 2 ^{x}}{1 - 2 ^{x}} : y = - 1, y = 5

Slant Asymptotes of

\frac{5 + 2 ^{x}}{1 - 2 ^{x}} :

None

Vertical : x = 0, Horizontal : y = - 1, y = 5

f (x) = \frac{1}{x - 3}

y = \frac{2}{3} x

13 x^{3} + 2 x^{2} - 12 x - 15

(x - 5)^{2} - 4

f (x) = \frac{3}{x ^{2} - 4}

What is the asymptotes of f(x)=(5+2^x)/(1-2^x) ?
The asymptotes of f(x)=(5+2^x)/(1-2^x) is Vertical: x=0,Horizontal: y=-1,y=5