What is the asymptotes of f(x)=(8x^2+1)/(2x^2+5x-3) ?

The asymptotes of f(x)=(8x^2+1)/(2x^2+5x-3) is Vertical: x=-3,x= 1/2 ,Horizontal: y=4

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asymptotes of f(x)=(8x^2+1)/(2x^2+5x-3)

asymptotes

f (x) = \frac{8 x ^{2} + 1}{2 x ^{2} + 5 x - 3}

Vertical : x = - 3, x = \frac{1}{2}, Horizontal : y = 4

Solution steps

Vertical asymptotes of

\frac{8 x ^{2} + 1}{2 x ^{2} + 5 x - 3} : x = - 3, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{8 x ^{2} + 1}{2 x ^{2} + 5 x - 3} : y = 4

Slant Asymptotes of

\frac{8 x ^{2} + 1}{2 x ^{2} + 5 x - 3} :

None

Vertical : x = - 3, x = \frac{1}{2}, Horizontal : y = 4

f (x) = \frac{( x - 3 ) ( x + 4 )}{x ^{2} - 4}

(x + 2) \cdot e^{\frac{1}{x}}

f (x) = (x - 3)^{3} + 1

f (x) = x^{2}

f (x) = \frac{5 x - 3}{2 x + 5}

What is the asymptotes of f(x)=(8x^2+1)/(2x^2+5x-3) ?
The asymptotes of f(x)=(8x^2+1)/(2x^2+5x-3) is Vertical: x=-3,x= 1/2 ,Horizontal: y=4