What is the extreme f(x)=13x^4-78x^2 ?

The extreme f(x)=13x^4-78x^2 is Minimum(-sqrt(3),-117),Maximum(0,0),Minimum(sqrt(3),-117)

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extreme f(x)=13x^4-78x^2

extreme points

f (x) = 13 x^{4} - 78 x^{2}

Minimum (- 3, - 117), Maximum (0, 0), Minimum (3, - 117)

Solution steps

f^{'} (x) = 52 x^{3} - 156 x

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

13 x^{4} - 78 x^{2} : - 117

Minimum (- 3, - 117)

Plug

x = 0

into

13 x^{4} - 78 x^{2} : 0

Maximum (0, 0)

Plug

x = 3

into

13 x^{4} - 78 x^{2} : - 117

Minimum (3, - 117)

Minimum (- 3, - 117), Maximum (0, 0), Minimum (3, - 117)

V (r) = \frac{4}{3} π r^{3}

f (x) = 4 - z^{2}

\frac{2 h ^{3} + 4 h ^{2} + 5 h}{h}

f (x) = \frac{x - 2}{x + 2}

f (x) = \frac{5 x ^{2}}{3 + x}

What is the extreme f(x)=13x^4-78x^2 ?
The extreme f(x)=13x^4-78x^2 is Minimum(-sqrt(3),-117),Maximum(0,0),Minimum(sqrt(3),-117)