What is the domain of f(x)=sqrt((x-1)(2x+3)) ?

The domain of f(x)=sqrt((x-1)(2x+3)) is x = 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((x-1)(2x+3))

domain

f (x) = (x - 1) (2 x + 3)

x \leq - \frac{3}{2} or x \geq 1

Interval Notation

(- \infty, - \frac{3}{2}] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{3}{2} or x \geq 1

The function domain

x \leq - \frac{3}{2} or x \geq 1

f (x) = - x^{2} + 4 x

(- 5, 2), (4, 5)

f (x) = x^{2} + 4

f (x) = \frac{( x - 2 )}{( x + 4 )}

cos (x + \frac{3 π}{4})

What is the domain of f(x)=sqrt((x-1)(2x+3)) ?
The domain of f(x)=sqrt((x-1)(2x+3)) is x<=-3/2 \lor x>= 1