What is the critical f(x)=21x^3-24x^2 ?

The critical f(x)=21x^3-24x^2 is x=0,x= 16/21

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critical f(x)=21x^3-24x^2

critical points

f (x) = 21 x^{3} - 24 x^{2}

x = 0, x = \frac{16}{21}

Solution steps

21 x^{3} - 24 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{16}{21}

Identify critical points not in

f (x)

domain

Domain of

21 x^{3} - 24 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{16}{21}

f (x) = 2 x + 7

\frac{6 x + 7}{5 x - 6}

f (x) = 7 (x + 5)

f (x) = x^{2} + 4 x + 2

3 x^{3} - 12 x^{2} - 15 x

What is the critical f(x)=21x^3-24x^2 ?
The critical f(x)=21x^3-24x^2 is x=0,x= 16/21