What is the inverse of f(x)=(sqrt(x)+2)/(sqrt(x)-6) ?

The inverse of f(x)=(sqrt(x)+2)/(sqrt(x)-6) is (4+24x+36x^2)/(x^2-2x+1)

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inverse of f(x)=(sqrt(x)+2)/(sqrt(x)-6)

inverse

f (x) = \frac{x + 2}{x - 6}

\frac{4 + 24 x + 36 x ^{2}}{x ^{2} - 2 x + 1}

Solution steps

y = \frac{x + 2}{x - 6}

Replace

x

with

y

x = \frac{y + 2}{y - 6}

Solve for

y, x = \frac{y + 2}{y - 6}

\frac{4 + 24 x + 36 x ^{2}}{x ^{2} - 2 x + 1}

f (x) = - 0.1 t^{2} + 1.2 t + 98.3

f (x) = 2 x x - 5

x - 1

x + 16

f (x) = (\frac{1}{3} x - 3)

What is the inverse of f(x)=(sqrt(x)+2)/(sqrt(x)-6) ?
The inverse of f(x)=(sqrt(x)+2)/(sqrt(x)-6) is (4+24x+36x^2)/(x^2-2x+1)