What is the inverse of (8x)/(x^2+25) ?

The inverse of (8x)/(x^2+25) is (4+sqrt(-25x^2+16))/x ,(4-sqrt(-25x^2+16))/x

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inverse of (8x)/(x^2+25)

inverse

\frac{8 x}{x ^{2} + 25}

\frac{4 + - 25 x ^{2} + 16}{x}, \frac{4 - - 25 x ^{2} + 16}{x}

Solution steps

y = \frac{8 x}{x ^{2} + 25}

Replace

x

with

y

x = \frac{8 y}{y ^{2} + 25}

Solve for

y, x = \frac{8 y}{y ^{2} + 25}

\frac{4 + - 25 x ^{2} + 16}{x}, \frac{4 - - 25 x ^{2} + 16}{x}

2 x^{6} - 5 x

x^{3} - 27 x

4 - 5 x

x^{2} + 2 x - 5

f (x) = 11 - x

What is the inverse of (8x)/(x^2+25) ?
The inverse of (8x)/(x^2+25) is (4+sqrt(-25x^2+16))/x ,(4-sqrt(-25x^2+16))/x