What is the domain of f(x)=(sqrt(x+8))/(x-4) ?

The domain of f(x)=(sqrt(x+8))/(x-4) is -8 4

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domain of f(x)=(sqrt(x+8))/(x-4)

domain

f (x) = \frac{x + 8}{x - 4}

- 8 \leq x < 4 or x > 4

Interval Notation

[- 8, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

- 8 \leq x < 4 or x > 4

2 e^{x} - 33 x - 5

f (x) = \frac{x}{2 x ^{2} - 5}

f (x) = ln (2 - x)

6 - x

\frac{2 x + 5}{3 x + 1}

What is the domain of f(x)=(sqrt(x+8))/(x-4) ?
The domain of f(x)=(sqrt(x+8))/(x-4) is -8<= x<4\lor x>4