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Popular >

extreme f(x)=-16x^2+40x+2

Solution

extreme points

f (x) = - 16 x^{2} + 40 x + 2

Solution

Maximum (\frac{5}{4}, 27)

Solution steps

f^{'} (x) = - 32 x + 40

Find intervals:

Increasing

: - \infty < x < \frac{5}{4},

Decreasing

: \frac{5}{4} < x < \infty

Plug

x = \frac{5}{4}

into

- 16 x^{2} + 40 x + 2 : 27

Maximum (\frac{5}{4}, 27)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-16x^2+40x+2 ?
The extreme f(x)=-16x^2+40x+2 is Maximum(5/4 ,27)