What is the asymptotes of f(x)=(x^2+1)/(3(x-8)) ?

The asymptotes of f(x)=(x^2+1)/(3(x-8)) is Vertical: x=8,Slant: y= 1/3 x+8/3

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asymptotes of f(x)=(x^2+1)/(3(x-8))

asymptotes

f (x) = \frac{x ^{2} + 1}{3 ( x - 8 )}

Vertical : x = 8, Slant : y = \frac{1}{3} x + \frac{8}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{3 ( x - 8 )} : x = 8

Horizontal Asymptotes of

\frac{x ^{2} + 1}{3 ( x - 8 )} :

None

Slant Asymptotes of

\frac{x ^{2} + 1}{3 ( x - 8 )} : y = \frac{1}{3} x + \frac{8}{3}

Vertical : x = 8, Slant : y = \frac{1}{3} x + \frac{8}{3}

4 x + 8 cos (x)

- \frac{1}{2 9 - x}

\frac{x ^{3} + 8}{x ^{2} + 9 x + 14}

f (x) = 10 - x

f (x) = 8 x^{2} + 7 x - 1

What is the asymptotes of f(x)=(x^2+1)/(3(x-8)) ?
The asymptotes of f(x)=(x^2+1)/(3(x-8)) is Vertical: x=8,Slant: y= 1/3 x+8/3