What is the domain of (sqrt(x))/(7x^2+6x-1) ?

The domain of (sqrt(x))/(7x^2+6x-1) is 0 1/7

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domain of (sqrt(x))/(7x^2+6x-1)

domain

\frac{x}{7 x ^{2} + 6 x - 1}

0 \leq x < \frac{1}{7} or x > \frac{1}{7}

Interval Notation

[0, \frac{1}{7}) \cup (\frac{1}{7}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{1}{7}, x = - 1

Combine real regions and undefined points for final function domain

0 \leq x < \frac{1}{7} or x > \frac{1}{7}

3 x^{2} - 12 x - 15

y = 3 x - 5

y + 2 = - 2 (x + 5)

x^{2} + 9

f (x) = 5 \cdot sin (x - \frac{5 π}{6})

What is the domain of (sqrt(x))/(7x^2+6x-1) ?
The domain of (sqrt(x))/(7x^2+6x-1) is 0<= x< 1/7 \lor x> 1/7