What is the range of ((x-1))/(x+2) ?

The range of ((x-1))/(x+2) is f(x) 1

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range of ((x-1))/(x+2)

range

\frac{( x - 1 )}{x + 2}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x - 1}{x + 2}

Inverse of

\frac{x - 1}{x + 2} : \frac{- 1 - 2 x}{x - 1}

\frac{- 1 - 2 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{- 1 - 2 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

x - 7

x^{2} - x - 6

f (x) = \frac{3 x + 6}{x - 1}

(- 10.4) (10.8)

\frac{2}{2 x - 3}

What is the range of ((x-1))/(x+2) ?
The range of ((x-1))/(x+2) is f(x)<1\lor f(x)>1